Question
Given the three planes:
– Plane P1: \(x + y + z = 6\) with normal vector \(\mathbf{n}_1 = (1, 1, 1)\),
– Plane P2: \(2x – y + 3z = 4\) with normal vector \(\mathbf{n}_2 = (2, -1, 3)\), and
– Plane P3: \(-x + 4y – z = 2\) with normal vector \(\mathbf{n}_3 = (-1, 4, -1)\),
identify which two planes intersect along a line forming a non-right angle. Provide your reasoning based on the normal vectors of the planes.
Hint
Examine the dot products of the normal vectors to determine if any pair are not perpendicular.
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Explanation
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Complete Answer
The planes P1 and P2 are the chosen pair since their normal vectors \( (1, 1, 1) \) and \( (2, -1, 3) \) are not perpendicular, indicating a non-right angle between them.
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