Hint
Hint
Recall that the dot product is given by \(\vec{A} \cdot \vec{B} = ||\vec{A}|| ||\vec{B}|| \cos\theta\). Solve for \(\theta\) using the inverse cosine.
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- Formula Booklet
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Answer
Complete Answer
\(\theta = \arccos\left(\frac{4}{5}\right) \approx 36.87^\circ\)
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