Hint
Recall that the modulus is the distance from the origin, \(r = \sqrt{a^2+b^2}\). For the argument \(\theta = \arctan\left(\frac{b}{a}\right)\), carefully consider the signs of both the real part \(a\) and the imaginary part \(b\) to identify the correct quadrant and adjust \(\theta\) accordingly.
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- Formula Booklet
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Complete Answer
\(r = 5, \theta \approx -53.13^\circ\) or in radians \(\theta \approx -0.93\)
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