Hint
Recall the change-of-base formula: \(\log_b(a) = \frac{\log_c(a)}{\log_c(b)}\). To express in terms of natural logarithm, use base \(c=e\).
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- Formula Booklet
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Complete Answer
\(\log_{10}(x) = \frac{\ln(x)}{\ln(10)}\); \(\log_{10}(2) \approx \frac{0.693}{2.303} \approx 0.301\)
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