Hint
Recall that the margin of error for a confidence interval for the mean is given by \(ME = z^* \times \frac{\sigma}{\sqrt{n}}\). Rearrange this formula to solve for \(n\).
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Complete Answer
The required sample size is \(n = \left( \frac{1.96 \times 15}{5} \right)^2 = 34.5744\), so rounding up to the nearest whole number gives \(n = 35\).
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