Hint
Recall that if \(A=PDP^{-1}\), then \(A^n=PD^nP^{-1}\), and that computing powers of a diagonal matrix is straightforward.
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- Formula Booklet
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Complete Answer
\(A^5=\begin{pmatrix} 32 & 211 & 0 \\ 0 & 243 & 0 \\ 0 & 0 & 1024 \end{pmatrix}\)
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