A geometric sequence has first term \(u₁ = 120\) and common ratio \(r = 0.9\).
(a) Find the value of the fifth term, \(u₅\). [2]
(b) Find the sum of the first 10 terms of the sequence. [2]
(c) Find the smallest number of terms, \(n\), for which the sum of the first \(n\) terms, \(Sₙ\), is greater than 1000. [2]
Question
Find the value of the fifth term, \(u₅\). [2]
Hint
Hint
Hint
Use the formula \(uₙ = u₁ \times r^{(n-1)}\) and substitute n = 5.
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Find the sum of the first 10 terms of the sequence. [2]
Hint
Hint
Hint
Use \(Sₙ = \frac{120(1 – r^n)}{1 – r}\) with n = 10.
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Question
Find the smallest number of terms, \(n\), for which the sum \(Sₙ\) is greater than 1000. [2]
Hint
Hint
Hint
Set up the inequality \(\frac{120(1 – 0.9^n)}{0.1} > 1000\) and solve for n using logarithms.
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