A cyclist accelerates uniformly from rest along a straight, horizontal road. After 5.0 s, the cyclist reaches a speed of 6.0 m s⁻¹. The total mass of the cyclist and bicycle is 80 kg.
(a) Calculate the acceleration of the cyclist. [1]
(b) Calculate the resultant force acting on the cyclist and bicycle. [1]
(c) Calculate the distance travelled by the cyclist in the first 5.0 s. [2]
(d) The cyclist then continues at a constant speed of 6.0 m s⁻¹. The cyclist stops pedalling and comes to rest due to a constant resistive force of 24 N. Determine the distance the cyclist travels while decelerating. [3]
Question
Calculate the acceleration of the cyclist. [1]
Hint
Hint
Hint
Use a = (v – u)/t with u = 0, v = 6.0 m/s, t = 5.0 s.
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1.2 m s⁻²
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Question
Calculate the resultant force acting on the cyclist and bicycle. [1]
Hint
Hint
Hint
Use F = ma with m = 80 kg and a from part (a).
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Calculate the distance travelled by the cyclist in the first 5.0 s. [2]
Hint
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Hint
Use s = ut + ½at² with u = 0, a from part (a), t = 5.0 s.
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Determine the distance the cyclist travels while decelerating under a constant resistive force of 24 N. [3]
Hint
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Hint
Use work–energy principle: F d = ½ m v², with v = 6.0 m/s.
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