Hint
First differentiate \(f(x)\) to find its stationary point by setting \(f'(x)=0\). Then calculate \(f(x)\) at x = 0.5, the stationary point, and x = 3 to compare the values.
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Complete Answer
The function has a unique stationary point at approximately \(x \approx 1.35\), which is a local minimum. Evaluating, \(f(0.5) \approx 1.80\), \(f(1.35) \approx 1.31\), and \(f(3) \approx 1.95\); hence the global minimum on \([0.5, 3]\) is at \(x \approx 1.35\) with \(f(1.35) \approx 1.31\).
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