Question
Evaluate the function for the following values:
– For \(x = 1\), since \(1 < 2\), use \(y = 3x + 1\).
– For \(x = 2\), use the second segment \(y = -2x + 7\) as \(x \geq 2\).
– For \(x = 3\), again use \(y = -2x + 7\).
Also, explain what happens at \(x = 2\) in terms of continuity.
Hint
Check each interval condition carefully and compare the value computed at \(x=2\) with the limit as \(x\) approaches 2 from the left.
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Answer
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Explanation
- Formula Booklet
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Complete Answer
For \(x = 1\): \(3(1)+1 = 4\); for \(x = 2\): \(-2(2)+7 = 3\); for \(x = 3\): \(-2(3)+7 = 1\). There is a jump discontinuity at \(x = 2\) because the left-hand limit is \(3(2)+1 = 7\) while the function value at \(x = 2\) is 3.
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Answer Explanation


