Question 2: Graph Transformations

00:00 5 marks

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Consider the function \(f(x)=x^2-6x+7\).
\(a\) Find the coordinates of the vertex of the graph of \(f\).
\(b\) Write down the equation of the axis of symmetry of the graph of \(f\).
\(c\) The graph of \(f\) is translated 3 units in the positive \(x\)-direction and 2 units in the negative \(y\)-direction. Find the equation of the translated graph, giving your answer in the form \(y=ax^2+bx+c\).

Part a

2 minutes 2 marks

Question

Find the coordinates of the vertex of \(f(x)=x^2-6x+7\).



Hint Hint

Hint

Use \(x=-\frac{b}{2a}\) to find \(x\), then substitute back into \(f(x)\) for \(y\).

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Complete Answer

The vertex is \((3,-2)\).

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Part b

1 minutes 1 marks

Question

Write down the equation of the axis of symmetry of \(f(x)\).



Hint Hint

Hint

Recall that the axis of symmetry is the vertical line passing through the vertex.

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Complete Answer

The axis of symmetry is \(x=3\).

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Part c

2 minutes 2 marks

Question

The graph of \(f(x)=x^2-6x+7\) is translated 3 units in the positive \(x\)-direction and 2 units in the negative \(y\)-direction. Find the equation of the translated graph in the form \(y=ax^2+bx+c\).



Hint Hint

Hint

Translate the vertex to get the new vertex, then write the equation in vertex form and expand it.

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Complete Answer

The translated graph has the equation \(y=x^2-12x+32\).

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