Question 3

00:00 4 marks

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Let \(f(x) = \sqrt{x-2}\) for \(x \ge 2\).
(a) Find \(f^{-1}(x)\). [2]
(b) State the domain and range of \(f^{-1}\). [2]

Part a

3 minutes 2 marks

Question

Find \(f^{-1}(x)\). [2]



Hint Hint

Hint

Set \(y = \sqrt{x-2}\) then swap x and y and solve for y.

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Complete Answer

\(f^{-1}(x) = x^2 + 2\)

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Part b

2 minutes 2 marks

Question

State the domain and range of \(f^{-1}\). [2]



Hint Hint

Hint

Remember that the domain of \(f^{-1}\) is the range of \(f\) and the range of \(f^{-1}\) is the domain of \(f\).

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Complete Answer

Domain of \(f^{-1}\): \(x \ge 0\); Range of \(f^{-1}\): \(y \ge 2\)

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