Hint
For part (a), use the perimeter formula \(2r + r\theta = 24\) to express \(\theta\) in terms of r and substitute into the sector area formula. In part (b), differentiate the expression obtained in part (a) and solve for r to maximize the area. In part (c), set up and evaluate the definite integral of \(3\sin(\pi x/2) + 1\) from 0 to 4.
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Complete Answer
Part (a): \(A = 12r – r^2\). Part (b): Maximum area occurs when \(r = 6\) cm, giving \(A = 36\) cm². Part (c): The area under the curve is 4.
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