Question
Calculate the coordinates of point P that divides the line segment AB internally in the ratio 2:3.
Hint
Use the formula: For internal division, \(P = \left(\frac{n x_A + m x_B}{m+n}, \frac{n y_A + m y_B}{m+n}\right)\), where the ratio AP:PB = m:n. Here, m = 2 and n = 3.
-
Answer
-
Mark Scheme
-
Explanation
- Formula Booklet
-
Answer
Complete Answer
P = (\(\frac{22}{5}\), \(\frac{39}{5}\)) = (4.4, 7.8)
-
Mark Scheme
-
Answer Explanation


