SHM Maximum Speed Determination

00:00 1 marks

A particle oscillates with simple harmonic motion (SHM). Its displacement $x$ varies with time $t$ according to the equation $x = x_0 \sin(\omega t)$. At which displacement is the particle’s speed a maximum?

A

$x = 0$
B

$x = \frac{x_0}{2}$
C

$x = \frac{x_0}{\sqrt{2}}$
D

$x = x_0$

Hint Hint

Hint

Recall that in SHM the speed is maximum when the cosine term is 1, which occurs when the displacement is zero.

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Answer Answer

Complete Answer

$x = 0$

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Answer Explanation Answer Explanation

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Common Errors Common Errors

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