Solving a Trigonometric Equation

00:00 3 marks

Solve the equation $2\sin^2(x) – 1 = 0$ for $x$ in the interval $0 \leq x < 2\pi$.

Hint Hint

Hint

Rearrange the equation to isolate $\sin^2(x)$ and remember to consider both positive and negative square roots.

Answer Answer
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Answer Answer

Complete Answer

The solutions are $x = \frac{\pi}{4}, \; \frac{3\pi}{4}, \; \frac{5\pi}{4}, \; \frac{7\pi}{4}$.

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Answer Explanation Answer Explanation

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Formula Booklet

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