Threshold Determination in Normal Distribution

00:00 3 marks

  • Exam Style - Paper 2
  • SL & HL
  • Tier 3
  • Normal distribution
  • Z-score
  • Inverse calculation
  • Threshold determination

A standardized test used to assess eligibility for a grant is known to follow a normal distribution with a mean score of 500 and a standard deviation of 100. The department aiming to award grants wishes to select candidates who score in the top 10% of the distribution. Calculate the minimum cutoff score required for eligibility.

Hint Hint

Hint

Recall that the z-score corresponding to the top 10% is approximately 1.28. Use the formula \(x = \mu + z\sigma\).

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Complete Answer

Approximately 628

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