A triangular field ABC has side \(AB = 85\text{ m}\) and side \(BC = 110\text{ m}\). The angle \(ABC\) is \(70^\circ\).
(a) Find the length of side AC. [3]
(b) Find the area of the field ABC. [3]
A vertical flagpole, BT, of height 18 m is located at corner B, with T being the top of the flagpole. The ground is horizontal.
(c) Calculate the angle of elevation of T from A. [4]
(d) Calculate the straight-line distance from C to T. [3]
(e) Point D lies on AC such that BD is perpendicular to AC. Calculate the length BD. [2]
Question
Find the length of side AC. [3]
Hint
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Use the cosine rule: \(AC^2 = AB^2 + BC^2 – 2 \cdot AB \cdot BC \cdot \cos(\angle ABC)\).
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AC = 114 m
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Find the area of the field ABC. [3]
Hint
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Use \(\text{Area}=\tfrac12\,AB\times BC\times\sin(\angle ABC)\).
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Area = 4390 m²
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Calculate the angle of elevation of T from A. [4]
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In right triangle ABT, use \(\tan(\angle BAT)=BT/AB\).
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Angle of elevation = 12.0°
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Calculate the straight-line distance from C to T. [3]
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In right triangle CBT, use \(CT=\sqrt{BC^2+BT^2}\).
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CT = 111 m
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Point D lies on AC such that BD is perpendicular to AC. Calculate the length BD. [2]
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Use the area of triangle ABC: Area = ½·AC·BD, then solve for BD.
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BD = 77.3 m
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